Question

计算（x^2-y^2/xy)^2/(x+y)*(x/x-y)^3

Answer 1

[（x^2-y^2)/xy]^2÷(x+y)^2×（x/x-y）^3
=[（x-y)(x+y)/xy]^2÷(x+y)^2×[x/(x-y)]^3
=(x-y)^2(x+y)^2/(xy)^2÷(x+y)^2×[x/(x-y)]^3
=(x-y)^2(x+y)^2/(xy)^2*1/(x+y)^2×[x/(x-y)]^3
=(x-y)^2/(xy)^2*[x/(x-y)]^3
=(x-y)^2/(xy)^2*x^3/(x-y)^3
=1/(xy)^2*x^3/(x-y)
=1/y^2*x/(x-y)
=x/[y^2(x-y)]
=x/(xy^2-y^3)
不懂的欢迎追问，如有帮助请采纳，谢谢!

追问

过程很详细 不过我的题里面的（x+y）不是平方 还是谢谢你

追答

不好意思,看错了,你再少乘个X+Y就可以了!
不懂的欢迎追问，如有帮助请采纳，谢谢!