Question

Oracle里面如何让一段日期按周、月、季度、年分组显示啊？求高手赐教，贴出正确sql追加高分！

我的代码如下：
select distinct to_char(dt, 'yyyy-mm-dd') as years,to_char(dt, 'iw') as weekfrom (select (to_date('2013-4-15', 'yyyy-mm-dd') + rownum - 1) dtfrom dual connect by rownum <= to_date('2013-7-15', 'yyyy-mm-dd') -to_date('2013-4-15', 'yyyy-mm-dd'))
ORDER BY years,week
想得到的效果如下（按周分组）：

Answer 1

select distinct to_char(dt, 'yyyy-mm-dd') as years,to_char(dt, 'iw') as week
from (select (to_date('2013-4-15', 'yyyy-mm-dd') + rownum - 1) dtfrom dual connect by rownum <= to_date('2013-7-15', 'yyyy-mm-dd') -to_date('2013-4-15', 'yyyy-mm-dd'))

group by to_char(dt, 'iw')
ORDER BY years,week

追问

你有在Oracle里试过吗？只加一个Group by 会报错！你可以自己写个实现效果就可以，不过还是谢谢了

追答

忘了，你把years 加上就是了，反正同一周肯定是同一年的
group by to_char(dt, 'yyyy-mm-dd'),to_char(dt, 'iw')

追问

运行结果：按天显得的老大，我要是的上图的效果！

追答

那你直接说你要显示星期天是不是?

追问

效果如图啊,从我指定的起始日期开始，每7天一分组啊

追答

我去，你还要指定时间啊，那就不好搞了
如果是星期天的话倒好弄
to_char(dt-(to_char(dt,'d')-1),'yyyy-mm-dd')

select distinct to_char(dt-(to_char(dt,'d')-1),'yyyy-mm-dd') as years,to_char(dt, 'iw') as week
from (select (to_date('2013-4-15', 'yyyy-mm-dd') + rownum - 1) dtfrom dual connect by rownum <= to_date('2013-7-15', 'yyyy-mm-dd') -to_date('2013-4-15', 'yyyy-mm-dd'))
group by to_char(dt-(to_char(dt,'d')-1),'yyyy-mm-dd'),to_char(dt, 'iw')
ORDER BY years,week

追问

呵，要求捉弄人啊。尽管没达到理想的效果，不过还是谢谢你，能有更好的解决办法就好了！

Answer 2

select distinct to_char(dt, 'yyyy') as years,to_char(dt, 'mm') as mounths,ceil(to_number(to_char(dt, 'mm')) / 3) jd,to_char(dt, 'iw') as week
from (select (to_date('2013-4-15', 'yyyy-mm-dd') + rownum - 1) dt
from dual connect by rownum <= to_date('2013-7-15', 'yyyy-mm-dd') -to_date('2013-4-15', 'yyyy-mm-dd'))

ORDER BY years,week

追问

我个不是我想要的效果。我需要按照如上图显示具体的年月日然后按周等条件分组。麻烦修改！谢谢