Question

PHP中，如何做出一个弹出对话框？

PHP中，如何做出一个弹出对话框？有一个表单，当必填项没填的时候怎么让他弹出一个对话框？

Answer 1

<form action="" method="post" name="myform" onsubmit="return test()"><input type="text" id="myinput"/><input type="submit" value="test"/></form><script language="javascript">function test(){var myinput=document.getElementById("myinput");if(myinput.value==null){alert("please input a value");return false;}else{return true}}</script>

Answer 2

如果验证用PHP在后端，那么就用Ajax；
<form name="myform" action="" method="post">
<p>用户：<input type="text" id="username" name="username" maxsize="20" onChange="nameInfor(this.value)"/> <span id="tip1"></span></p>
<p>密码：<input type="password" name="password" maxsize="50" /> <span id="tip2"></span></p>
<input type="button" name="rgt" value="提交" onclick="dosubmit('subInfor')" />
<input type="button" name="back" value="返回" onclick="dosubmit('back')"/>
</form>

Answer 3

echo "<script>alert('弹出来咯~~');</script>";