Question

与十进制数677等值的十六进制数是。。。？？怎么算啊？？

Answer 1

#include <stdio.h>
void ba();
void er();
void shiliu();
int num[50];
int i,shu;
int count = 0;

void main()
{
int chioce;
do
{
printf("\n0.退出、1.十进制--二进制、2.十进制--八进制、3.十进制--十六进制\n");
printf("选择的功能：");
scanf("%d",&chioce);
switch (chioce)
{
case 1: er();
break;
case 2: ba();
break;
case 3: shiliu();
break;
}

} while ( !chioce == 0);
printf("退出\n");
printf("\n");
}

void er()
{
count = 0;
printf("请输入一个十进制的数：");
scanf("%d",&shu);

do
{
num[count] = shu%2;
shu = shu/2;
count++;
}while (shu!=0);
printf("转换为二进制为：");
for (i = count - 1;i >= 0;i--)
{
printf("%d",num[i]);
}
printf("\n");
}

void ba()
{
count = 0;
printf("请输入一个十进制的数：");
scanf("%d",&shu);

do
{
num[count] = shu%8;
shu = shu/8;
count++;
}while (shu!=0);
printf("转换为八进制为：");
for (i = count - 1;i >= 0;i--)
{
printf("%d",num[i]);
}
printf("\n");

}
void shiliu()
{
count = 0;
printf("请输入一个十进制的数：");
scanf("%d",&shu);

do
{
num[count] = shu%16;
shu = shu/16;
count++;
}while (shu!=0);
printf("转换为十六进制为：");
for (i = count - 1;i >= 0;i--)
{
switch (num[i])
{
case 10:printf("A");
break;
case 11:printf("B");
break;
case 12:printf("C");
break;
case 13:printf("D");
break;
case 14:printf("E");
break;
case 15:printf("F");
break;
default:printf("%d",num[i]);
}

}
printf("\n");
}

Answer 2

677除以16得到2 10 5转换成十六进制就是2A5

Answer 3

用667除以16余数做个位，商在除以16余数做第二位，以此循环知道商为零就可以了