Question

如图所示，直线AB，CD相交于点O，OE垂直AB于O，且∠DOE=4∠COE，求∠AOD的度数

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Answer 1

∵∠DOE=4∠COE
∴∠DOE+4∠COE=5∠COE=180°
∴∠COE=36°∠DOE=144°
∠AOD=180-∠DOB
=180-(∠DOE-90)
=270-∠DOE
=126°