(1+√3i)³等于多少,要过程
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=2³(1/2+√3i/2)³
=8(e^(π/3))^3
=8e^π
=8*-1
=-8
原理e^a=cosa+ i sina
=8(e^(π/3))^3
=8e^π
=8*-1
=-8
原理e^a=cosa+ i sina
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=(1+√3i)(1+√3i)²
=(1+√3i)(-2+2√3i)
=-2(1+√3i)(1-√3i)
=-2*4
=-8
=(1+√3i)(-2+2√3i)
=-2(1+√3i)(1-√3i)
=-2*4
=-8
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(1+√3i)³
=(1+√3i)²(1+√3i)
=2√3i(1+√3i)
=2√3i+6i²
=2√3i-6
=(1+√3i)²(1+√3i)
=2√3i(1+√3i)
=2√3i+6i²
=2√3i-6
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