Question

数学化简

求这两题化简..其实有答案 但是我想看过程.

Answer 1

解：﹙a﹚﹙x－1﹚/﹙x²＋4x－5﹚＝﹙x－1﹚/﹙x－1﹚﹙x＋5﹚＝1/﹙x＋5﹚
﹙b﹚10/﹙x²＋x－6﹚－2/﹙x－2﹚
＝2/﹙x－2﹚[5/﹙x＋3﹚－1]
＝2/﹙x－2﹚·﹙2－x﹚/﹙x＋3﹚
＝﹣2/﹙x＋3﹚.

Answer 2

第一题
=﹙x－1﹚/﹙x－1﹚﹙x＋5﹚=1/﹙x＋5﹚
第二题
=10/（x-2)（x+3)-2/(x-2)=[10-2(x+3)]/（x-2)（x+3)=(4-2x)/（x-2)（x+3)=-2(x-2)/（x-2)（x+3)
=-2/（x+3)

Answer 3

(x-1）/(x^2+4x-5)=(x-1）/(x+5)(x-1)=1/(x+5)
10/(x^2+x-6)-2/（x-2）=10/(x+3)(x-2)-(2x+6)/(x+3)(x-2)=-(2x-4)/(x+3)(x-2)=-2/(x+3)

Answer 4

用十字相乘法
x^2+4x-5=(x+5)(x-1)
约去x-1即可

Answer 5

(a)原式=(x-1)/[（x-1）*(x+5)]=1/(x+5)
(b)原式=10/[(x-2)(x+3)]-2/(x-2)=[10-2(x+3)]/[(x-2)(x+3)]=(4-2x)/[(x-2)(x+3)]=-2（x-2）/[(x-2)(x+3)]
= -2/(x+3)

Answer 6

‍(x-1)(x+5) /x-1 (x+3)(x-2) x-2/10x+28