Question

java编程实现图形界面

上面能显示用户名和密码，密码如果匹配成功，就输出登陆成功，否则输出密码或账户名错误！

Answer 1

import java.awt.Container;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JFrame;
import javax.swing.JOptionPane;
import javax.swing.JPasswordField;
import javax.swing.JTextField;
import javax.swing.JButton;
public class mi
{
private static String username;
private static String password ;
private static JTextField []t={
new JTextField("账号：",8),new JTextField(10),
new JTextField("密码：",8),new JPasswordField(10)};

public static void main (String args[]){
JFrame app=new JFrame("账号密码演示程序");
app.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
app.setSize(280,120);
Container c=app.getContentPane();
c.setLayout(new FlowLayout());

t[0].setEditable(false);
t[2].setEditable(false);
for(int i=0;i<4;i++)
c.add(t[i]);t[1].setText("");

JButton[]b={new JButton("确定"),new JButton("重置")};
c.add(b[0]);c.add(b[1]);
app.setLocationRelativeTo(null);
app.setVisible(true);

b[1].addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
t[1].setText("");
t[3].setText("");
}
});
// 登录按钮加事件监听器
b[0].addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
username = t[1].getText();
password = t[3].getText();
//判断用户名密码是否正确
if (username.equals("数字") && password.equals("123")) {
JOptionPane.showMessageDialog(null, "登陆成功！", "消息",
JOptionPane.INFORMATION_MESSAGE);

} else {
JOptionPane.showMessageDialog(null, "用户名或密码错误！", "错误",
JOptionPane.ERROR_MESSAGE);
}
}
}); }

}