Question

(x+y+z)(-x+y+z)(x-y+z)(x+y-z)详 细 解题步骤！！

Answer 1

你好

(x+y+z)(-x+y+z)(x-y+z)(x+y-z)
=[x+（y+z）] [(y+z）-x] [x-（y-z)] [x+（y-z)]
=[(y+z）²-x²][x²-（y-z）²]
=(y+z）²x²-(y+z）²（y-z）²-x⁴+x²（y-z）²
=x²[(y+z）²+（y-z）²]-（y²-z²）²-x⁴
=x²（2y²+2z²）-y⁴+2y²z²-z⁴-x⁴
=-x⁴-y⁴-z⁴+2x²y²+2x²z²+2y²z²

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