Question

如图所示,已知∠1=∠2,∠3=∠4,∠5=∠6,求证：EB//FD.

Answer 1

∠3=∠4,CE//BD,∠B=∠EAB=∠C,AB//CD,∠2=∠AGF=∠1,(令G为AB与FD的交点），所以EB//FD.good luck to you,best wishes to your study------说的比较简练，请见谅

Answer 2

∵∠3=∠4,∠5=∠6,

∴∠3+∠5=∠4+∠6

而∠3+∠5+∠7=∠4+∠6+∠2=180º

∴∠7=∠2

又∵∠1=∠2

∴∠7=∠1

∴EB//FD