
已知x-3y=0,求(2x+y)(x-y)/x^2-2xy+y^2的值
(2x+y)(x-y)已知x-3y=0,求—————的值x²-2xy+y²(2x+y)(x-y)—————x²-2xy+y²...
(2x+y)(x-y)
已知x-3y=0,求 ————— 的值
x²-2xy+y²
(2x+y)(x-y)
—————
x²-2xy+y² 展开
已知x-3y=0,求 ————— 的值
x²-2xy+y²
(2x+y)(x-y)
—————
x²-2xy+y² 展开
1个回答
展开全部
x-3y=0
x=3y
原式=(2x+y)(x-y)/(x²-2xy+y²)
=(2×3y+y)(3y-y)/[(3y)²-2×3y×y+y²]
=7y×2y/(9y²-6y²+y²)
=14y²/(4y²)
=7/2
x=3y
原式=(2x+y)(x-y)/(x²-2xy+y²)
=(2×3y+y)(3y-y)/[(3y)²-2×3y×y+y²]
=7y×2y/(9y²-6y²+y²)
=14y²/(4y²)
=7/2
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