Question

因式分解 求解

Answer 1

因式分解？
应该是计算或者化简吧？
解：
(x²+3x+9)/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)
=(x²+3x+9)/(x²-27)-6/(x-9)-(x-1)/[2(x+3)]
=(x²+3x+9)/(x²-27)-[12(x+3)+(x-1)(x-9)]/[2(x-9)(x+3)]
=(x²+3x+9)/(x²-27)-(x²+2x+45)/[2(x-9)(x+3)]
=[2(x²+3x+9)(x-9)(x+3)-(x²+2x+45)(x²-27)]/[2(x-9)(x+3)(x²-27)]
=[2(x²+3x+9)(x²-6x-27)-(x²+2x+45)(x²-27)]/[2(x-9)(x+3)(x²-27)]
=(2x^4-6x^3-72x²-270x-486-x^4-2x^3-18x²+54x+1215)/(2x^4-12x^3-108x²+324x+1458)
=(x^4-8x^3-90x²-216x+729)/(2x^4-12x^3-108x²+324x+1458)