Question

因式分解的两个题目 大家帮帮忙

要过程

Answer 1

1
原式=(4xyz)²-3²=(4xyz+3)(4xyz-3)

2
原式=[5(m+n+2)]²-[4(m-n-2)]²
=(5m+5n+10+4m-4n-8)(5m+5n+10-4m+4n+8)
=(9m+n+2)(m+9n+18)

Answer 2

16x²y²z²-9
=（4xyz）²-3²
=（4xyz+3）（4xyz-3）

25（m+n+2）²-16（m-n-2）²
=[5（m+n+2）]²-[4（m-n-2）]²
=[5（m+n+2）+4（m-n-2）][5（m+n+2）-[4（m-n-2）]
=[5m+5n+10+4m-4n-8][5m+5n+10-4m+4n+8]
=[9m+n+2][m+9n+18]