Question

servlet3.0 取不到form传回的值

package servlett;

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
* Servlet implementation class index
*/
@WebServlet("/index")
public class index extends HttpServlet {
private static final long serialVersionUID = 1L;

/**
* Default constructor.
*/
public index() {
// TODO Auto-generated constructor stub
}

/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String aaString= request.getAttribute("asd").toString();
}

/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}

}
今天试验了下 用input submit可以在servlet用getparamater取到,
但是改用javascript提交就取不到form里面的值了

Answer 1

你可以system.out.printf一下aaString的值，如果没有 你就改为request.getParameter("asd")；再看，aaString的指，还有 去掉toString();你传过来的就是String干嘛还要toString();改吧，不行就把错误代码弄上来，或者doPost里面加个this.doGet(request,response);

Answer 2

Form表单提交的数据，在Servlet中使用request.getParameter("asd");方法来获取相应的值；而request.getAttribute(key)方法是从request作用域中获取指定key的值。

Answer 3

request.getAttribute 应该换成request.getParemeter(“asd”);