Question

定义一个结构体变量(包括年月日)，计算改日在当年中是第几天？运行后不是想要的结果

c程序源代码如下：但运行后不是想要的结果，暂时找不到原因:
#include <stdio.h>
#include <stdlib.h>
typedef struct
{
int month;
int day;
int year;
}DATE;
DATE date;
int main(int argc, char *argv[])
{
int days;
printf("please input the date:\n");
scanf("%d,%d,%d",&date.year,&date.month,&date.day);
switch(date.month)
{
case 1:
days = date.day;
break;
case 2:
days = date.day + 31;
break;
case 3:
days = date.day + 31 + 28;
break;
case 4:
days = date.day + 31 + 28 +31;
break;
case 5:
days = date.day + 31 + 28 + 31 + 30;
break;
case 6:
days = date.day + 31 + 28 + 31 + 30 + 31;
break;
case 7:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30;
break;
case 8:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30 + 31;
break;
case 9:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31;
break;
case 10:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30;
break;
case 11:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31;
break;
case 12:
days = date.day + 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30;
break;
}

if (date.year%4 == 0 && date.year%100 != 0 || date.year%400 == 0)
{
if(date.month >= 3)
{
days += 1;
}
printf("\nthe day in this year is the %dth day!\n",days);
}
system("PAUSE");
return 0;
}

Answer 1

printf("\nthe day in this year is the %dth day!\n",days);你得从是否为闰年的判断中拿出来吧，放到

system("PAUSE"); 前面，要不你的显示只是在闰年中显示，其他的不是闰年的不显示

Answer 2

if (date.year%4 == 0 && date.year%100 != 0 || date.year%400 == 0)
{
if(date.month >= 3)
{
days += 1;
}
printf("\nthe day in this year is the %dth day!\n",days);
}
改成
if (date.year%4 == 0 && date.year%100 != 0 || date.year%400 == 0)
{
if(date.month >= 3)
{
days += 1;
}
}
printf("\nthe day in this year is the %dth day!\n",days);