cos(π/3+a)=-3/5,π/3<π/3+α<5π/6, sin(π/3+a)=4/5
sin(2π/3-β)=5/13, ,-π/3<2π/3-β<π/6 cos(2π/3-b)=12/13.
因为cos( (π/3+α)+(2π/3-β) )=cos(a-b+π)=-cos(a-b)=-cos(b-a)
cos( (π/3+α)cos(2π/3-β)-sin(π/3+a)sin(2π/3-β)=-cos(b-a)
-3/5*12/13-4/5*5/13=-cos(b-a)
cos(b-a)=56/65