Question

当P点在圆X^2+Y^2=1上变动时,它与定点Q(0,3)相连,线段PQ的中点M的轨迹方程为?

方程化为标准式

Answer 1

设p(x1,y1) ,M(x,y)
2x=x1,2y-3=y1 (2x)^2+(2y-3)^2=1
x^2+y^2-3y+2=0

Answer 2

设P点为(X,Y),
则M为(X/2,Y+3/2),

Answer 3

4x^2+(2y-3)^2=1