化简1/(b+c)(c/b-b/c)+1/(a+c)(a/c-c/a)+1/(a+b)(b/a-a/b)要有过程谢谢
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1/(b+c)(c/b-b/c)+1/(a+c)(a/c-c/a)+1/(a+b)(b/a-a/b)
=1/(b+c) × (c²-b²)/bc +1/(a+c) × (a²-c²)/ac +1/(a+b) × (b²-a²)/ab
=(c-b)/bc + (a-c)/ac + (b-a)/ab
=(ac-ab+ab-bc+bc-ac)/abc
=0/abc
=0
=1/(b+c) × (c²-b²)/bc +1/(a+c) × (a²-c²)/ac +1/(a+b) × (b²-a²)/ab
=(c-b)/bc + (a-c)/ac + (b-a)/ab
=(ac-ab+ab-bc+bc-ac)/abc
=0/abc
=0
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