Question

请编写一个函数，实现有1到100的所有奇数的累加，并在控制台输出对应的结果

Answer 1

int sum = 0;//和
for (int i = 1; i <= 100; )//i从1开始循环，每次循环累加2，正好是奇数
{
sum = sum + i;
i = i + 2;
}
Console.WriteLine("1到100奇数和为："+sum);
Console.ReadLine(); 这是C#的代码，仅供参考

Answer 2

int sun=0;
for (int i = 1; i < 100; i+=2) {
sun+=i;
}
System.out.println(sun);

Answer 3

VB.NET: Public Function AddOdds() As IntegerDim Sum As Integer =0 For I As Integer = 1 To 100 If(I Mod 2 =0) Sum = Sum + I End If NextReturn SumEnd Function

Answer 4

#include<stdio.h>int main(){int i,sum=0;for(i=1;i<=100;i++) if(i%2)sum+=i;printf("%d\n",sum);return 0;}