Question

jquery解析json的事

ajax返回的data的值为
[{
"id":1,
"text":"Java",
"desc":"Write once, run anywhere"
},{
"id":2,
"text":"C#",
"desc":"One of the programming languages designed for the Common Language Infrastructure"
},{
"id":3,
"text":"Ruby",
"selected":true,
"desc":"A dynamic, reflective, general-purpose object-oriented programming language"
},{
"id":4,
"text":"Perl",
"desc":"A high-level, general-purpose, interpreted, dynamic programming language"
},{
"id":5,
"text":"Basic",
"desc":"A family of general-purpose, high-level programming languages"
}]

怎么用jquery得到第三个对象的text值，说白了就是Ruby

Answer 1

$.each(data, function(entryIndex, entry){
  if(entryIndex == 2){
    var text = entry.text;
  }
});
  也可以把所有的text放到一个数组中然后在用

Answer 2

不需要解析的，你这个ajax返回的就是一个数组，里面是json数据类型的对象集合
直接 data[2].text 就能得到你想要的第三个对象的text值

Answer 3

data[2].text 无误
记得在回调函数里用

追问

什么叫回调函数？

追答

$.post('xxx.action', {param:'xxx'}, function(data){
console.log(data[2].text);

})

Answer 4

data[2].text

追问

TypeError: data[2] is undefined
console.info(data[2].text);

报这个错 ，而且能够得到data[2]，就是得不到data[2].text)