Question

当x=1时,ax的五次方+bx的三次方+cx+1=5 则x=-1时ax的五次方+bx的三次方+cx+1=？

Answer 1

解：∵ 当 x = 1 时，a x ⁵ + b x ³ + c x + 1 = 5
∴ a × 1 ⁵ + b × 1 ³ + c × 1 = 4
a + b + c = 4
∴ 当 x = - 1 时，a x ⁵ + b x ³ + c x + 1
= a × （- 1）⁵ + b × （- 1）³ + c × （- 1）+ 1
= - a - b - c + 1
= -（a + b + c）+ 1
= - 4 + 1
= - 3

Answer 2

当x=1时 ax^5+bx^3+cx=4

所以，当x=-1时 ax^5+bx^3+cx=-4
所以，当x=-1时ax^5+bx^3+cx+1=-3

Answer 3

x=1 ax^5+bx^3+cx+1=a+b+c+1=5 a+b+c=4
x=-1 ax^5+bx^3+cx+1=-a-b-c+1=-(a+b+c)+1=-4+1=-3

Answer 4

x=-1时ax的五次方+bx的三次方+cx+1=
-3