
解方程1、2
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解:
(1):
3/4{4/3[1/2(x-1/4)-8]}=(3/2)x
4/3[1/2(x-1/4)-8]=(3/2)x·4/3
1/2(x-1/4)-8=(3/2)x·4/3·3/4
(1/2)x - 1/8 - 8 =(3/2)x
(3/2)x-(1/2)x=1/8 + 8
x=8又1/8
(2)1/2{x-(1/3)[x-(1/4)x+(1/6)]-2/3}=x+(3/4)
1/2{x-(1/3)[(3/4)x+(1/6)]-2/3}=x+(3/4)
1/2{x-(1/4)x-(1/18)-2/3}=x+(3/4)
(3/4)x-(1/18)-2/3=2x+(3/2)
(-5/4)x=20/9
x=-16/9
(1):
3/4{4/3[1/2(x-1/4)-8]}=(3/2)x
4/3[1/2(x-1/4)-8]=(3/2)x·4/3
1/2(x-1/4)-8=(3/2)x·4/3·3/4
(1/2)x - 1/8 - 8 =(3/2)x
(3/2)x-(1/2)x=1/8 + 8
x=8又1/8
(2)1/2{x-(1/3)[x-(1/4)x+(1/6)]-2/3}=x+(3/4)
1/2{x-(1/3)[(3/4)x+(1/6)]-2/3}=x+(3/4)
1/2{x-(1/4)x-(1/18)-2/3}=x+(3/4)
(3/4)x-(1/18)-2/3=2x+(3/2)
(-5/4)x=20/9
x=-16/9
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