Question

C++分析下列程序，指出错误的地方并予以改正,在线等，谢谢啦

6. 找出下面程序中的错误并说明理由。
class base{
protected：
int p;};
void fun()
{
base b;
int x=b.p;
}

7. 分析下列程序，指出错误的地方并予以改正。
class base{
public：
int b;};
class base1：public base{　}
class base2：public base{　}
class derived：public base1：public base2{
public：
int f();
};
main()
{
derived d;
d.b();
d.base：：b;
}

8. 如果希望下列程序的运行结果如下，请将程序补充完整。
Base¢s cons.
Derived¢s cons.
Derived¢s des.
Base¢s des.
class Base{
public:
Base(){cout<< “Base¢s cons.”<<endl;}
{cout<< “Base¢s des.”<<endl;}
};
class Derived:public Base{
public:
Derived(){cout<< “Derived¢s cons.”<<endl;}
~Derived(){cout<< “Derived¢s des.”<<endl;}
};
void main()
{ Base *ptr=
delete ptr;}
8. 如果希望下列程序的运行结果如下，请将程序补充完整。
Base¢s cons.
Derived¢s cons.
Derived¢s des.
Base¢s des.
class Base{
public:
Base(){cout<< “Base¢s cons.”<<endl;}
__________________________{cout<< “Base¢s des.”<<endl;}
};
class Derived:public Base{
public:
Derived(){cout<< “Derived¢s cons.”<<endl;}
~Derived(){cout<< “Derived¢s des.”<<endl;}
};
void main()
{ Base *ptr= _______________________
delete ptr;}
麻烦说下第6怎么改，第8刚才没写清楚，麻烦再看下。。。

Answer 1

6、
int x=b.p;
这句错，不能访问保护类型的成员

7、
#include <stdio.h>
#include <stdlib.h>
#include <iostream.h>

class base{
public:
int b;};
class base1:public base{ };//类定义的结束要有分号
class base2:public base{ };//类定义的结束要有分号
class derived:public base1,public base2//两个public之间要用逗号而不是冒号
{
public:
int f();
};
main()
{
derived d;
//d.b(); //b是数据成员，不能当函数进行调用
d.base1::b;//d.base::b; //b有二义性，应该指明是base1的还是base2的
}