Question

关于51单片机C语言 数码管 4*4按键 简单的密码锁

密码是1 请在这个程序上加
#include <reg51.h>
#include <INTRINS.H>
#define PORT_P0 P0
#define PORT_P1 P1
unsigned char a[11]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0xc0};
sbit hang1=P1^4;
sbit hang2=P1^5;
sbit hang3=P1^6;
sbit hang4=P1^7;

sbit lie1=P1^0;
sbit lie2=P1^1;
sbit lie3=P1^2;
sbit lie4=P1^3;

sbit COM1=P2^5;
sbit COM2=P2^4;
sbit COM3=P2^3;
sbit COM4=P2^2;
sbit COM5=P2^1;
sbit COM6=P2^0;

unsigned int anjian_number=0,hang_number=0;
void delay(unsigned int t)
{
unsigned int i;

while(t--)
{

for (i=0;i<60;i++)

{}
}
}
void disp_number(unsigned long number)
{

unsigned long number1,number2,number3,number4,number5,number6;
number1=(number/100000);
number2=((number/10000)%10);
number3=((number/1000)%10);
number4=((number/100)%10);
number5=((number/10)%10);
number6=(number%10);
COM1=0;
PORT_P0=a[number1];
delay(1);
COM1=1;
COM2=0;
PORT_P0=a[number2];
delay(1);
COM2=1;
COM3=0;
PORT_P0=a[number3];
delay(1);
COM3=1;
COM4=0;
PORT_P0=a[number4];
delay(1);
COM4=1;
COM5=0;
PORT_P0=a[number5];
delay(1);
COM5=1;
COM6=0;
PORT_P0=a[number6];
delay(1);
COM6=1;
}
void anjian()
{
if(lie1==0)
{
delay(20);
if(lie1==0)
{
anjian_number=0+hang_number;
disp_number(anjian_number);
}
while(!lie1);
}
if(lie2==0)
{
delay(20);
if(lie2==0)
{
anjian_number=1+hang_number;
disp_number(anjian_number);
}
while(!lie2);
}
if(lie3==0)
{
delay(20);
if(lie3==0)
{
anjian_number=2+hang_number;
disp_number(anjian_number);
}
while(!lie3);
}
if(lie4==0)
{
delay(20);
if(lie4==0)
{
anjian_number=3+hang_number;
disp_number(anjian_number);
}
while(!lie4);
}
}
void main()
{

P2=0xff;
P1=0xff;
while(1)
{

hang1=0;
hang_number=0;
anjian();
hang1=1;

hang2=0;
hang_number=4;
anjian();
hang2=1;

hang3=0;
hang_number=8;
anjian();
hang3=1;

hang4=0;
hang_number=12;
anjian();
hang4=1;

disp_number(anjian_number);
}
}

Answer 1

关于51单片机C语言 数码管 4*4按键 简单的密码锁

这个问题我知道

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Answer 2

表示没看明白你的问题

Answer 3

把问题说清楚一点