Question

因式分解2x²+xy-y²-4x+5y-6

Answer 1

2x²+xy-y²-4x+5y-6

=(x＋y)(2x－y)-4x+5y-6(第一次十字相乘)
=（x＋y－3）（2x－y＋2）(第二次十字相乘)
两次十字相乘
x y x＋y ﹣3
× ×

2x ﹣y 2x－y 2

不懂的还可以问！满意请及时采纳！ O(∩_∩)O

Answer 2

2x²+xy-y²-4x+5y-6
=(2x-y)(x+y)-6x+3y+2x-2y-6
=(2x-y)(x+y)-3(2x-y)+2x-2y-6
=(2x-y)(x+y-3)+2(x+y-3)
=(x+y-3)(2x-y+2)

追问

4﹙x－y+1﹚+y﹙y－2x﹚