求第十题怎么做
2014-05-13
展开全部
∠b = ∠a + 15°;∠c = ∠b +60° = ∠a + 15° + 60° = ∠a + 75°
又 ∠a + ∠b + ∠c = 180°
∴ ∠a + ∠a + 15° + ∠a + 75° = 180°
即: 3∠a = 90°
∴ ∠a = 30°
∠b = 30° + 15° = 45°
∠c = 45° + 60° = 105°
又 ∠a + ∠b + ∠c = 180°
∴ ∠a + ∠a + 15° + ∠a + 75° = 180°
即: 3∠a = 90°
∴ ∠a = 30°
∠b = 30° + 15° = 45°
∠c = 45° + 60° = 105°
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询