Question

一道简单的acm题，可是我老是通不过oj

Input
Inputcontains multiple test cases, and one case one line. Each case starts with aninteger N, and then N integers follow in the same line.

Output
For each testcase you should output the sum of N integers in one line, and with one line ofoutput for each line in input.

Sample Input
4 1 2 3 4
5 1 2 3 4 5

Sample Output
10
15

Answer 1

#include<stdio.h>
 
int main()
{
    int n,x,sum;
    while(scanf("%d",&n)!=EOF)
    {
        sum = 0;
        while(n--)
        {
            scanf("%d",&x);
            sum+=x;
        }
        printf("%d/n",sum);
    }
    return 0;
}

学习一下输入输出就好，欢迎交流。

追问

oj也报错，还有你的换行应该是\n

追答

给个题目网址吧，我试一下。

追问

http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=1§ionid=1&problemid=3006

追答

#include<stdio.h>
  
int main()
{
    int n,x,sum;
    while(scanf("%d",&n)!=EOF)
    {
        sum = 0;
        while(n--)
        {
            scanf("%d",&x);
            sum+=x;
        }
        printf("%d\n",sum);
    }
    return 0;
}

这个是可以AC的，你试试哈。