Question

重复数据中，取每一类型的最晚一条数据 Oracle

如下图中B、C、D三列数据。C列数据存在重复，C列数据中数据分为三类，要求获取每一类数据中时间最晚（B类数据中最晚的一条数据）的一条对应的D列数据值。
请问各位大侠SQL语句怎么写？？？如果回答正确，会再次赠送财富值。

Answer 1

select TA.D from table TA, (select max(B) as B,C from table group by C) TB where TA.B=TB.B and TA.C=TB.C;

Answer 2

select t1.dfrom tab t1 ,(select max(b) b ,c from tab st group by c ) t2where t1.b = t2.b and t1.c = t2.c

Answer 3

select d, b from (select d, b, max(b) over (partition by c) b_max from t1) a where b=b_max;

Answer 4

select d from table where b in (select max(b) from table group by trunc(b)) order by b;

Answer 5

SELECT D FROM TABLE_NAME WHERE B IN (SELECT MAX(B) FROM TABLE_NAME GROUP BY C)