Question

小弟需要大神帮助。哪位大神可以帮小弟编写Java程序，谢谢了，





Answer 1

名字 自己改   ，  包名 也可以自己改

追问

谢谢啊！您真是雪中送炭啊

Answer 2

package com.work.demo1;

public class Rabbit extends Animal{

@Override
public void swiming() {
System.out.println("那只"+animalColour+"的，名叫"+animalName+"的兔子正在叽叽的叫");
}

@Override
protected void eat() {
System.out.println("兔子是"+animalClass+"，爱吃胡萝卜");
}

@Override
protected void cry() {
System.out.println("兔八哥和兔斯基也是会游泳的！");
}

}

package com.work.demo1;

public class Frog extends Animal{

@Override
public void swiming() {
System.out.println("那只"+animalColour+"的，名叫"+animalName+"的青蛙正在呱呱的叫");
}

@Override
protected void eat() {
System.out.println("青蛙是"+animalClass+"，爱吃昆虫");
}

@Override
protected void cry() {
System.out.println("虽然不是鱼，但青蛙也是泳坛高手！");
}

}

package com.work.demo1;

public interface ISwiming {
void swiming();
}

package com.work.demo1;

public abstract class Animal implements ISwiming{
protected String animalName;
protected String animalColour;
protected String animalClass;

protected abstract void eat();
protected abstract void cry();
}

package com.work.demo1;

public class AnimalTest {
static Animal rabbit = new Rabbit();
static Animal frog = new Frog();
public static void init(){
rabbit.animalColour = "黑色";
rabbit.animalName="美人";
rabbit.animalClass="哺乳类";
frog.animalClass="绿色";
frog.animalColour="大兵";
frog.animalName="非哺乳类";
}
public static void main(String[] args) {
rabbit.eat();
rabbit.cry();
System.out.println("-----------------------");
frog.eat();
frog.cry();
frog.swiming();
}

}

追问

谢谢了

Answer 3

给的这么显而易见，定义接口和父类然后去继承跟实现啊；比如他们都是动物，吧动物做父类，然后都继承动物，动物油两个方法叫 和 吃；