请教两道题 5
Thechild(who,whom)wethoughtwaslostwasfoundinthenextbook.Thewoman(who,whom)wethoughtto...
The child (who, whom) we thought was lost was found in the next book.
The woman (who, whom) we thought to be (she, her) turned out to be her sister.
请问这两道题怎么选?为什么? 请附上解释好吗 谢谢 展开
The woman (who, whom) we thought to be (she, her) turned out to be her sister.
请问这两道题怎么选?为什么? 请附上解释好吗 谢谢 展开
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1.解:A为CuCl2;B为Cu(OH)2;C为CuS;D为AgCl。CuCl2溶于水后水合铜离子,呈浅蓝色;在氯化铜溶液中加入NaOH溶液可得浅蓝色Cu(OH)2沉淀,Cu(OH)2能溶于盐酸,也能溶于氨水生成铜氨配离子。CuCl2溶液中通入H2S,有黑色CuS沉淀生成,CuS难溶于盐酸而溶于热浓HNO3中。CuCl2溶液中加入Ba(NO)3溶液,无沉淀生成,加入AgNO溶液时有白色AgCl沉淀生成,AgCl也溶于氨水生成银氨离子。有关反应:Cu2++2OH- →Cu(OH)2↓Cu(OH)2+2H+ → Cu2++2 H2OCu2++H2S → CuS↓+2H+3CuS+8HNO3 → 3Cu(NO3)2+3S↓+2NO↑+4H2O Ag+ +Cl- → AgCl↓2.AgNO3+NaCl=NaNO3+AgCl↓AgCl+3NH3·H2O=Ag(NH3)2OH+NH4Cl+2H2O Ag(NH3)2OH +KBr = AgBr↓ + KOH + 2NH3 ↑ AgBr +2 Na2S2O3 = Na3[Ag(S2O3)2] + NaBr (分步反应:AgBr + Na2S2O3 → Na[Ag(S2O3)]+NaBr Na[Ag(S2O3)] + Na2S2O3 → Na3[Ag(S2O3)2] )
Na3[Ag(S2O3)2] + KCl = AgCl↓ + Na2S2O3+KNaS2O3
AgCl + 2KCN = K[Ag(CN)2] + KCl
2K[Ag(CN)2] + Na2S = Ag2S↓ + 2KCN + 2NaCN
这样可以么?
Na3[Ag(S2O3)2] + KCl = AgCl↓ + Na2S2O3+KNaS2O3
AgCl + 2KCN = K[Ag(CN)2] + KCl
2K[Ag(CN)2] + Na2S = Ag2S↓ + 2KCN + 2NaCN
这样可以么?
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