化简!!!
1个回答
2014-07-18
展开全部
cos100°/(cos5°√(1-sin100°))
=cos100/(cos5*√(sin50-cos50)^2)
=cos100/(cos5(sin50-cos50))
=(cos50+sin50)(cos50-sin50)/(cos5(sin50-cos50)
=-(sin50+sin50)/cos5
=cos100/(cos5*√(sin50-cos50)^2)
=cos100/(cos5(sin50-cos50))
=(cos50+sin50)(cos50-sin50)/(cos5(sin50-cos50)
=-(sin50+sin50)/cos5
更多追问追答
追答
希望采纳呀
希望采纳呀
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询