请教高中数学问题,求高手解答,要有详细步骤哦~
展开全部
1
a>b,两边同时加上c得:
a+c>b+c
选C
2.
用韦达定理:
5/6=(1/2)+(1/3)=5/(-a); ===>a= - 6
1/6=(1/2)*(1/3)=c/a=c/(-6)===>c= - 1
选B
3
(x-1)/(x+2)<0; 等价于
(x-1)(x+2)<0
-2<x<1
选C
4
令t=sinx (t>0)
y=t+(1/t)≥2√t(1/t)=2 ; (当且仅当t=(1/t),即t=1时取等号)
y(min)=2
选B
5
抛物线必须开口向下,判别式小于零即;
{m+1<0
{(m-1)^2-12(m+1)(m-1)<0
===>
{m<-1
{m^2-2m+1-12m^2+12<0
===>
{m<-1
{11m^2+2m-13>0
===>
{m<-1
{(11m+13)(m-1)>0
===>
{m<-1
{m>1,或m<-13/11
m<-13/11
选C
a>b,两边同时加上c得:
a+c>b+c
选C
2.
用韦达定理:
5/6=(1/2)+(1/3)=5/(-a); ===>a= - 6
1/6=(1/2)*(1/3)=c/a=c/(-6)===>c= - 1
选B
3
(x-1)/(x+2)<0; 等价于
(x-1)(x+2)<0
-2<x<1
选C
4
令t=sinx (t>0)
y=t+(1/t)≥2√t(1/t)=2 ; (当且仅当t=(1/t),即t=1时取等号)
y(min)=2
选B
5
抛物线必须开口向下,判别式小于零即;
{m+1<0
{(m-1)^2-12(m+1)(m-1)<0
===>
{m<-1
{m^2-2m+1-12m^2+12<0
===>
{m<-1
{11m^2+2m-13>0
===>
{m<-1
{(11m+13)(m-1)>0
===>
{m<-1
{m>1,或m<-13/11
m<-13/11
选C
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询