Question

51单片机 c语言 按键和数码管显示

如何用按键按1数码管显示1再按0数码管显示10再按1数码管显示101 就是如何显示0

Answer 1

#include<reg51.h>
unsigned char led[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
void led_display(unsigned char  num);
unsigned char  key_scan();
sbit led1=P2^0;
sbit led2=P2^1;
void main()
{
unsigned char led_key;
P1=0;
while(1)
    {
led_key=key_scan();
led_display(led_key);
    }
}
void led_display(unsigned char  num)
{
unsigned char ten,single;
int delay;
ten=num/10;
single=num%10;
delay=100;
for(delay=200;delay>0;delay--)
{
P0=led[ten];
led1=0;   
led1=1;
P0=led[single];
led2=0;
led2=1;
}
}
 /////////////////////////////////////////
unsigned char key_scan(void)
{
unsigned char temp,key;
P1=0xfe;
temp=P1&0xf0;
if(temp!=0xf0)
    {
switch(temp)
        {
        case 0xe0: key=1;
            break;
        case 0xd0: key=2;
            break;
        case 0xb0: key=3;
            break;
        case 0x70: key=4;
        }
return key;
    }
P1=0xfd;
temp=P1&0xf0;
if(temp!=0xf0)
    {
switch(temp)
        {
        case 0xe0: key=5;
            break;
        case 0xd0: key=6;
            break;
        case 0xb0: key=7;
            break;
        case 0x70: key=8;
        }
return key;
    }

P1=0xfb;
temp=P1&0xf0;
if(temp!=0xf0)
    {
switch(temp)
        {
        case 0xe0: key=9;
            break;
        case 0xd0: key=10;
            break;
        case 0xb0: key=11;
            break;
        case 0x70: key=12;
        }
return key;
    }
P1=0xf7;
temp=P1&0xf0;
if(temp!=0xf0)
    {
switch(temp)
        {
        case 0xe0: key=13;
            break;
        case 0xd0: key=14;
            break;
        case 0xb0: key=15;
            break;
        case 0x70: key=16;
        }
return key;
    }
}

你好！很高兴为您解答！我有欢迎采纳！！以上传附件！！

追问

并不是我想要的结果哦

Answer 2

只有两个按键？
数码管有几个？共阴、共阳？

追问：我没学移位 请给个 【 每按键一次，移位一次}的编程 谢谢

下面的即是：

disp_buff [7] = disp_buff [6];
disp_buff [6] = disp_buff [5];
disp_buff [5] = disp_buff [4];
disp_buff [4] = disp_buff [3];
disp_buff [3] = disp_buff [2];
disp_buff [2] = disp_buff [1];
disp_buff [1] = disp_buff [0];
disp_buff [0] = key;

全部程序，可参考：

http://hi.baidu.com/do_sermon/item/65af71290819959eb6326365

Answer 3

12864液晶的要不要。