Question

如何对Scala中集合进行排序

Answer 1

这两天碰到3个一样的问题，所以我直接用之前回答的答案。
可以用sorted的方法

scala> val list = List(3,2,6,1,7,5,2)
list: List[Int] = List(3, 2, 6, 1, 7, 5, 2)

scala> list.sorted
res0: List[Int] = List(1, 2, 2, 3, 5, 6, 7)

scala> val m = Map(-5->2,1->5,6->4,2->8,9->7)
m: scala.collection.immutable.Map[Int,Int] = Map(1 -> 5, 6 -> 4, 9 -> 7, 2 -> 8,
-5 -> 2)

scala> m.toList.sorted foreach{println}
(-5,2)
(1,5)
(2,8)
(6,4)
(9,7)

scala> val arr = Array(4,3,6,2,9,0,-1,-4)
arr: Array[Int] = Array(4, 3, 6, 2, 9, 0, -1, -4)

scala> arr.sorted
res2: Array[Int] = Array(-4, -1, 0, 2, 3, 4, 6, 9)