1个回答
2015-08-12
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x/(x+y) + y/(x-y) - y²/(x² - y²)
= [ x(x-y)+y(x+y) - y²] / (x²-y²)
= x²/(x² - y²)
= 1 / [ 1 - (y/x)² ]
= 1/ [ 1 - (3/4)² ]
= 16 / 7
= [ x(x-y)+y(x+y) - y²] / (x²-y²)
= x²/(x² - y²)
= 1 / [ 1 - (y/x)² ]
= 1/ [ 1 - (3/4)² ]
= 16 / 7
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