Question

cout出错，哪位给看看？

#include<iostream>
#include<vector>
#include<string>
using namespace std;

struct test
{int seg;
int shape;
float r1,r2,l,t;
}t1;

void main()
{cout<<"段数"<<endl;
cin>>t1.seg;
cout<<"形状：1圆柱，2圆锥，3凸形，4凹形"<<endl;
cin>>t1.shape;
cout<<"r1,r2,l,t"<<endl;
cin>>t1.r1>>t1.r2>>t1.l>>t1.t;

vector<test> svec;
svec.push_back(t1);
vector<test>::iterator it=svec.begin();
vector<test>::iterator it_end=svec.end();
for(;it!=it_end;++it)
cout<<*it<<'\n';//***这里提示有错误！！！no operator"<<" matches this operands！！！
cout<<endl;

}
是怎么回事啊？

Answer 1

你必须重载输出操作才行，结构体不能整体输出的：

#include<iostream>
#include<vector>
#include<string>
using namespace std;

struct test
{int seg;
    int shape;
    float r1,r2,l,t;
}t1;

ostream& operator<<(ostream &out, const struct test &t) {
    out<<"shape:"<<t.shape<<";r1:"<<t.r1<<";r2:"<<t.r2<<";l:"<<t.l<<";t:"<<t.t;
    return out;
}

void main()
{cout<<"段数"<<endl;
    cin>>t1.seg;
    cout<<"形状：1圆柱，2圆锥，3凸形，4凹形"<<endl;
    cin>>t1.shape;
    cout<<"r1,r2,l,t"<<endl;
    cin>>t1.r1>>t1.r2>>t1.l>>t1.t;

    vector<test> svec;
    svec.push_back(t1);
    vector<test>::iterator it=svec.begin();
    vector<test>::iterator it_end=svec.end();
    for(;it!=it_end;++it)
        cout<<*it<<'\n';//***这里提示有错误！！！no operator"<<" matches this operands！！！
    cout<<endl;
    
}