Question

jqgrid subGridRowExpanded出来的子表格如何获取选中的行？

Answer 1

子表格也是一个jqgrid，你可以像操作主表格一样操作子表格的 subGridRowExpanded: function(subgrid_id, row_id) { // we pass two parameters // subgrid_id is a id of the div tag created whitin a table data // the id of this elemenet is a combination of the "sg_" + id of the row // the row_id is the id of the row // If we wan to pass additinal parameters to the url we can use // a method getRowData(row_id) - which returns associative array in type name-value // here we can easy construct the flowing var subgrid_table_id, pager_id; subgrid_table_id = subgrid_id+"_t"; pager_id = "p_"+subgrid_table_id; $("#"+subgrid_id).html("<table id='"+subgrid_table_id+"' class='scroll'</table<div id='"+pager_id+"' class='scroll'</div"); jQuery("#"+subgrid_table_id).jqGrid({ url:"subgrid.php?q=2&id="+row_id, datatype: "xml", colNames: ['No','Item','Qty','Unit','Line Total'], colModel: [ {name:"num",index:"num",width:80,key:true}, {name:"item",index:"item",width:130}, {name:"qty",index:"qty",width:70,align:"right"}, {name:"unit",index:"unit",width:70,align:"right"}, {name:"total",index:"total",width:70,align:"right",sortable:false}], rowNum:20, pager: pager_id, sortname: 'num', sortorder: "asc", 然后子表格的操作就是jQuery("#"+subgrid_table_id).jqGrid('getGridParam','selarrrow');