Question

怎么样使用java来获得百度地图开源接口中，IP定位返回的结果？

例如：
访问：http://api.map.baidu.com/location/ip?ak=F454f8a5efe5e577997931cc01de3974&ip=202.198.16.3&coor=bd09ll

返回了：
{"address":"CN|\u5409\u6797|\u957f\u6625|None|CERNET|1|None","content":{"address":"\u5409\u6797\u7701\u957f\u6625\u5e02","address_detail":{"city":"\u957f\u6625\u5e02","city_code":53,"district":"","province":"\u5409\u6797\u7701","street":"","street_number":""},"point":{"x":"125.31364243","y":"43.89833761"}},"status":0}
如何把address的值\u5409\u6797\u7701\u957f\u6625\u5e02放入变量str中？
求高手们解答。。
大神们回答得太好了，我已经下载了jar包，但是我不太会定义那个类，里面有包含关系，还麻烦大家再帮我把，谢谢啦！

Answer 1

gson，先按 那格式，定义一个类BaiduGeo

Gson gson = new Gson();
result = gson.fromJson(sTotalString, BaiduGeo.class);

Answer 2

楼上是正解啊，json的转成map格式，然后用键值对的形式取出来就可以了

Answer 3

额 这个就是json的啦

var s = '{"address":"CN|\u5409\u6797|\u957f\u6625|None|CERNET|1|None","content":{"address":"\u5409\u6797\u7701\u957f\u6625\u5e02","address_detail":{"city":"\u957f\u6625\u5e02","city_code":53,"district":"","province":"\u5409\u6797\u7701","street":"","street_number":""},"point":{"x":"125.31364243","y":"43.89833761"}},"status":0}';

var jsonObj = eval("("+s+")");

你就可以得到的啦

就是的啦

var str = jsonObj.address;