Question

3x²y²+2xy-7x²y²-3/2xy+2+4x²y²,其中x=2，y=1/4

请问那题怎么解答？？

Answer 1

3x²y²+2xy-7x²y²-3/2xy+2+4x²y²
=(3+4-7)x²y²+(2-3/2)xy+2
=1/2xy+2
=2又1/4

追问

若a²b m和a n b³是同类项，则m n=_______.

追答

a²b^m 与a^nb³是同类项， 则n=2,m=3 所以m-n=3-2=1

Answer 2

3x²y²+2xy-7x²y²-3/2xy+2+4x²y²=1/2xy+2=1/2*2*1/4+2=9/4

追问

若a²b m和a n b³是同类项，则m n=_______.