Question

已知a/b=c/d=e/f=2，且b+d+f≠0，求a-2c+3e/b-2d+3f的值

Answer 1

b-2d+3f=0,就不成立
所以应该是b-2d+3f≠0，不是=b+d+f≠0
a=2b,c=2d,e=2f,那么a-2c+3e=2b-2*2d+3*2f=2b-4d+6f=2(b-2d+3f)
a-2c+3e/b-2d+3f=2(b-2d+3f)/b-2d+3f=2

Answer 2

题目是不是抄错了啊?不是b-2d+3f≠0吗?
如果是b-2d+3f≠0的话就是这样的
∵a/b=c/d=e/f=2∴a=2b c=2d e=2f
∴a-2c+3e=2(b-2d+3f)
∴(a-2c+3e)/(b-2d+3f)=[2(b-2d+3f)]/b-2d+3f=2
∴(a-2c+3e)/(b-2d+3f)的值为2

Answer 3

a=2b,c=2d,e=2f,那么a-2c+3e=2b-2*2d+3*2f=2b-4d+6f=2(b-2d+3f)
a-2c+3e/b-2d+3f=2(b-2d+3f)/b-2d+3f=2

Answer 4

【此题快速解答】
a/b=-2c/（-2d）=3e/（3f)=2
(a-2c+3e)/(b-2d+3f)=2

Answer 5

∵ a/b=c/d=e/f=2;
∴ a=2b; c=2d; e=2f;
∴a-2c+3e/b-2d+3f
=2b-4d+6f/d-2d+3f
=2