Question

(x–1)(x–2)(x–3）(x–4)–24 因式分解 详细点 谢谢

Answer 1

(x–1)(x–2)(x–3）(x–4)–24
=(x–1)(x–4)(x–2)(x–3）-24
=（x.X-5x+4)(x.X-5x+6）-24
=（x.X-5x）的平方+10（x.X-5x）+24-24
=（x.X-5x）的平方+10（x.X-5x）
=（x.X-5x）（x.X-5x+10）
=x（.X-5）（x.X-5x+10）

Answer 2

(x–1)(x–2)(x–3)(x–4)–24
=(x–1)(x–4)(x–2)(x–3)-24
=(x²-5x+4)(x²-5x+6)-24
=(x²-5x+5-1)(x²-5x+5+1)-24
=(x²-5x+5)²-1-24
=(x²-5x+5)²-5²
=(x²-5x+5+5)(x²-5x+5-5)
=(x²-5x+10)(x²-5x)
=x(x-5)(x²-5x+10)