Question

用C++编程图案出现先错误求解!!!

#include"stdio.h"
#include"conio.h"
int main()
{
printf(" ┏━┓┏━┓\n");
printf(" ┃┃┃┃┃┃\n");
printf(" ┃┃┃┃┃┃\n");
printf("┏┛┃┗┛┃┗┓\n");
printf("┃ ┃ \n");
printf("┃ ┃ \n");
printf("┃━━ ﹏ ━━ ┃ \n");
printf("┃ ┃ \n");
printf("┗━━━━━━┛ \n");
getch()
return 0;
}

Answer 1

getch()  这句的后面少了分号 ; 加上就好了

Answer 2

不要用#include"conio.h"了，另外getch（）也不要了，getchar（）更不要加，因为加这些东西的话，底下会有缓冲，不如不加。，代码如下：

#include"stdio.h"
//#include"conio.h"
int main()
{
printf(" ┏━┓┏━┓\n");
printf(" ┃┃┃┃┃┃\n");
printf(" ┃┃┃┃┃┃\n");
printf("┏┛┃┗┛┃┗┓\n");
printf("┃ ┃ \n");
printf("┃ ┃ \n");
printf("┃━━ ﹏ ━━ ┃ \n");
printf("┃ ┃ \n");
printf("┗━━━━━━┛ \n");
//getchar();
return 0;
}

追问

请问如果想让图案变色要如何编程?

追答

我不知道你用的编译器是不是在linux下的，不过这些宏定义你可以试试：
#define NONE "\033[m"
#define RED "\033[0;32;31m"
#define LIGHT_RED "\033[1;31m"
#define GREEN "\033[0;32;32m"
#define LIGHT_GREEN "\033[1;32m"
#define BLUE "\033[0;32;34m"
#define LIGHT_BLUE "\033[1;34m"
#define DARY_GRAY "\033[1;30m"
#define CYAN "\033[0;36m"
#define LIGHT_CYAN "\033[1;36m"
#define PURPLE "\033[0;35m"
#define LIGHT_PURPLE "\033[1;35m"
#define BROWN "\033[0;33m"
#define YELLOW "\033[1;33m"
#define LIGHT_GRAY "\033[0;37m"
#define WHITE "\033[1;37m"
int main()
{
printf("\033[32m 卡尔 \033[31m" "hello world!\n" "\033[m");
return 0;
}全部是使输出变换呈现相应的颜色

Answer 3

#include<stdio.h>
int main()

{

printf("  ┏━┓┏━┓\n");

printf("  ┃┃┃┃┃┃\n");

printf("  ┃┃┃┃┃┃\n");

printf("┏┛┃┗┛┃┗┓\n");

printf("┃            ┃ \n");

printf("┃            ┃ \n");

printf("┃━━ ﹏ ━━┃ \n");

printf("┃            ┃ \n");

printf("┗━━━━━━┛ \n");

getchar();

return 0;

}

试试这个

Answer 4

getch();//除了这里少两个分号，没有其他错误啊？
return 0;

Answer 5

gtech()函数后少个分号。