跪求一个C语言程序输出“生日快乐”(TC)

 我来答
匿名用户
2013-09-07
展开全部
#include "Conio.h"
#include "graphics.h"
#define closegr closegraph
char sheng32S[]={
/* 以下是 '生' 的 32点阵宋体 字模,128 byte */
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0xC0,0x80,0x00,
0x00,0x80,0x80,0x00,0x00,0x80,0x80,0x00,
0x01,0x00,0x80,0x00,0x01,0x00,0x80,0x20,
0x00,0x00,0x80,0x00,0x02,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x04,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0xC0,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x18,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char ri32S[]={
/* 以下是 '日' 的 32点阵宋体 字模,128 byte */
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x01,0x00,0x00,0x80,
0x01,0x00,0x00,0x80,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char kuai32S[]={
/* 以下是 '快' 的 32点阵宋体 字模,128 byte */
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x03,0x00,0x60,0x00,
0x02,0x00,0x40,0x00,0x02,0x00,0x40,0x00,
0x00,0x00,0x40,0x00,0x00,0x00,0x40,0x00,
0x00,0x00,0x40,0x40,0x00,0x00,0x40,0x40,
0x00,0x40,0x40,0x40,0x00,0x20,0x40,0x40,
0x00,0x10,0x40,0x40,0x00,0x00,0x40,0x40,
0x10,0x00,0x40,0x40,0x30,0x00,0x40,0x40,
0x00,0x00,0x40,0x40,0x00,0x00,0x40,0x48,
0x00,0x00,0x40,0x00,0x00,0x00,0x40,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,
0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,
0x00,0x01,0x02,0x00,0x02,0x02,0x00,0x00,
0x03,0x00,0x01,0x00,0x03,0x00,0x00,0xC0,
0x03,0x00,0x00,0x60,0x03,0x00,0x00,0x30,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};
char le32S[]={
/* 以下是 '乐' 的 32点阵宋体 字模,128 byte */
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,
0x00,0x00,0x0F,0x00,0x01,0x00,0x00,0x00,
0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,
0x01,0x00,0x00,0x00,0x01,0x00,0x40,0x00,
0x01,0x00,0x40,0x00,0x01,0x00,0x40,0x00,
0x03,0x00,0x40,0x00,0x02,0x00,0x40,0x00,
0x02,0x00,0x40,0x10,0x02,0x00,0x40,0x00,
0x00,0x00,0x40,0x00,0x00,0x00,0x40,0x00,
0x00,0x00,0x40,0x00,0x00,0x30,0x40,0x00,
0x00,0x20,0x41,0x00,0x00,0x40,0x40,0x80,
0x00,0x80,0x40,0x40,0x01,0x00,0x40,0x60,
0x02,0x00,0x40,0x30,0x04,0x00,0x40,0x30,
0x00,0x00,0x40,0x00,0x00,0x00,0x40,0x00,
0x00,0x03,0xC0,0x00,0x00,0x01,0x80,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};

void drawmat(char *mat,int matsize,int x,int y,int color)
/*依次:字模指针、点阵大小、起始坐标(x,y)、颜色*/
{int i,j,k,n; <br/>n=(matsize-1)/8+1; <br/>for(j=0;j<matsize;j++) <br/>for(i=0;i<n;i++) <br/>for(k=0;k<8;k++) <br/>if(mat[j*n+i]&(0x80>>k)) /*测试为1的位则显示*/ <br/>putpixel(x+i*8+k,y+j,color); <br/>}

void initgr(void)
{
int gd = DETECT, gm = 0;
registerbgidriver(EGAVGA_driver);
initgraph(&gd, &gm, "");
}

int main(void)
{
initgr(); /* BGI初始化 */
drawmat(sheng32S,32,50,50,11);
drawmat(ri32S,32,100,100,11);
drawmat(kuai32S,32,150,150,11);
drawmat(le32S,32,200,200,11);
getch();
closegr();
return 0;
}
匿名用户
2013-09-07
展开全部
#include<stdio.h>
main()
{
printf("祝你生日快乐!\n");
}
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
匿名用户
2013-09-07
展开全部
如果用TC输入汉字,会出现汉字乱码,所以最好用C++,cout<<"祝你生日快乐!!"<<endl。
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
匿名用户
2013-09-07
展开全部
你要来干吗嘀..是要给人惊喜吗?如是是那样的话用vb更好
msgbox("祝你生日快乐!!")
把这句保存在文本再把txt文件名改为vbs就得了
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
匿名用户
2013-09-07
展开全部
TC可以输入汉字的。。。
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
收起 2条折叠回答
收起 更多回答(3)
推荐律师服务: 若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询

为你推荐:

下载百度知道APP,抢鲜体验
使用百度知道APP,立即抢鲜体验。你的手机镜头里或许有别人想知道的答案。
扫描二维码下载
×

类别

我们会通过消息、邮箱等方式尽快将举报结果通知您。

说明

0/200

提交
取消

辅 助

模 式