求答案,在线等,第二题
2个回答
追答
BC = 5, CD = 4, BD = 3
根据勾股定理
三角形BDC是直角三角形,且角BDC是直角
所以三角形ADC也是直角三角形
则AD^2 + CD^2 = AC^2
又因为AB = AC
所以AD^2 + CD^2 = AC^2 = AB^2 = (AD + BD)^2
AD^2 + 4^2 = (AD + 3)^2
AD = 7/6
AB = AD + BD = 7/6 + 3 = 25/3
AC = AB = 25/3
BC = 5
周长 = AB + AC + BC = 25/3 + 25/3 + 5 = 65/3
错了
AB = AD + BD = 7/6 + 3 = 25/6
AC = AB = 25/6
BC = 5
周长 = AB + AC + BC = 25/6 + 25/6 + 5 = 40/3
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