初三一元二次方程--因式分解法
①3x^2=4x;②x(x-1)+3(x-1)=0;③3(x-5)^2=2(5-x);④3x^2-4x=2x;⑤x(x-6)=2(x-8)过程,谢谢...
①3x^2=4x;②x(x-1)+3(x-1)=0;③3(x-5)^2=2(5-x);④3x^2-4x=2x;⑤x(x-6)=2(x-8)
过程,谢谢 展开
过程,谢谢 展开
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①3x^2=4x;
3x²-4x=0
x(3x-4)=0
x1=0,x2=4/3
②x(x-1)+3(x-1)=0;
(x-1)(x+3)=0
x1=1
x2=-3
③3(x-5)^2=2(5-x);
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)(3x-13)=0
x1=5
x2=13/3
④3x^2-4x=2x;
3x²-4x-2x=0
3x²-6x=0
3x(x-2)=0
x1=0
x2=2
⑤x(x-6)=2(x-8)
x²-6x-2x+16=0
x²-8x+16=0
(x-4)²=0
x1=x2=4
3x²-4x=0
x(3x-4)=0
x1=0,x2=4/3
②x(x-1)+3(x-1)=0;
(x-1)(x+3)=0
x1=1
x2=-3
③3(x-5)^2=2(5-x);
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)(3x-13)=0
x1=5
x2=13/3
④3x^2-4x=2x;
3x²-4x-2x=0
3x²-6x=0
3x(x-2)=0
x1=0
x2=2
⑤x(x-6)=2(x-8)
x²-6x-2x+16=0
x²-8x+16=0
(x-4)²=0
x1=x2=4
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