Question

a(a+1)(a+2)(a+3)+1因式分解

快，要过程

Answer 1

您好：

a(a+1)(a+2)(a+3)+1
=（a²+3）（a²+3a+2）+1
=(a²+3)²+2(a²+3)+1
=(a²+3+1)²
=（a²+4）²

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Answer 2

a(a+1)(a+2)(a+3)+1
=[a(a+3)][(a+1)(a+2)]+1
=(a²+3a)(a²+3a+2)+1
=[(a²+3a+2)-2](a²+3a+2)+1
=(a²+3a+2)²-2(a²+3a+2)+1
=[(a²+3a+2)-1]²
=(a²+3a+1)²