Question

php用“opendir”函数打开时出现错误

<?php
$mulum="111"
$name="myadmin";
$f_u="/";
$yu="myself";
$mulu=$yu.$f_u.$name;
$tihuan="1.gif";
$key=array(".asp",".asa",".php",".jsp",".html",".htm");
if(strstr($tihuan,$key)==false){
echo"<script>alert('上传图像为不可以上传的类型！');history.back();</script>";
}else{
opendir("$mulu");
if(is_dir("$mulum"){
echo"<script>alert('相同目录已存在!');history.back();</script>";
}else{
mkdir("$mulum");
closedir("$mulu");
}}
?>执行完后出先Parse error: syntax error, unexpected T_VARIABLE in J:\phphj\APMServ5.2.6\www\htdocs\cs\diy.php on line 3
是怎么回事？

Answer 1

你的$mulum="111"后面少了一个";"