Question

在三角形ABC中,∠A=2∠B=3∠C,则∠A= ,∠B= ,∠C 。

在三角形ABC中,∠A=2∠B=3∠C,则∠A= ,∠B= ,∠C 。求度数 注意三角形的内角和是180°

Answer 1

解:∵∠A=2∠B=3∠C.
∴∠A=3∠C;∠B=(3/2)∠C.
∵∠A+∠B+∠C=180度,即3∠C+(3/2)∠C+∠C=180度.
∴∠C=∠(360/11)度
∠B=(3/2)∠C=(540/11)度
∠A=3∠C=(1080/11)度.

Answer 2

.......
∠A+ ∠B+ ∠C = 180
∠A+ ∠A/2 + ∠A/3 = 180
=> ∠A = 1080/11 => ∠B = 540/11, ∠C = 360/11

Answer 3

同意楼下观点。

Answer 4

∠A=2∠B=3∠C
∠A+∠B+∠C
=∠A+1/2∠A+1/3∠A
=11/6∠A
=180°

Answer 5

∠A+ ∠B+ ∠C= ∠A+ 1/2∠A+1/3 ∠A=11/6 ∠A=180°
∴ ∠A=180°÷11/6=1080°/11
∠B=540°/11
∠C=360°/11