java编程基础,输入1-7显示对应星期,求大神的源码和解体思路
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import java.util.Scanner;
public class Temp {
public String getWeek(int i) {
switch(i) {
case 1: return "Monday";
case 2: return "Tuesday";
case 3: return "Wednesday;";
case 4: return "Thursday";
case 5: return "Friday";
case 6: return "Saturday";
case 7: return "Sunday";
default: return "Unknown week";
}
}
public static void main(String[] args) {
Temp t = new Temp();
Scanner scanner = new Scanner(System.in);//输入1-7
System.out.println(t.getWeek(scanner.nextInt()));//显示对应星期
}
}
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直接写一个方法啊
private String showDay(int i){
String today = null;
switch(i){
case 1:
today = "星期一";
case 2:
today = "星期二";
case 3:
today = "星期三";
case 4:
today = "星期四";
case 5:
today = "星期五";
case 6:
today = "星期六";
case 7:
today = "星期日";
}
return today;
}
private String showDay(int i){
String today = null;
switch(i){
case 1:
today = "星期一";
case 2:
today = "星期二";
case 3:
today = "星期三";
case 4:
today = "星期四";
case 5:
today = "星期五";
case 6:
today = "星期六";
case 7:
today = "星期日";
}
return today;
}
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这串代码能行么?
追答
可以运行 你调用这个方法执行就可以了
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将1~7 和对应的星期放到map对象中,然后,用if ... else ...判断,或者switch case语句分析,根据输入码,从map中取值输出
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