Question

解不等式：x2+1分之2x+1大于0 x2+2分之2x+1大于1

Answer 1

(2x+1)/(x^2+1)>0,
x^2+1>0,上式变为2x+1>0,
2x>野野-1,
∴x>-1/厅脊册2.

(2x+1)/(x^2+2)>1,
x^2+2>0,两边都乘以x^2+2,得扮宏
2x+1>x^2+2,
∴x^2-2x+1